(4^3/4)^3=4n

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Solution for (4^3/4)^3=4n equation: 



(4^3/4)^3=4n

We move all terms to the left:

(4^3/4)^3-(4n)=0

We multiply all the terms by the denominator


-4n*4)^3+(4^3=0

Wy multiply elements

-16n^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-32}=0$

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